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**Time and Distance Problems (Important Points and Tips to note)**

- Out of the three quantities (Speed / Distance / Time), we are required to find one. Information regarding the other two will be provided in the question stem.
- Usually involve something / someone moving at a constant or average speed.
- Understand the concept behind the formula rather than just using it blindly.
- If there is more than one unknown quantity, do not blindly assign another variable to it. Look for ways in which you can express that quantity in therms of the quantities already present. Assign another variable to it only if this is not possible.

Now let's do some practice problems. Try to solve these on your own. You can check

**Solutions with Detailed explanations from here.****A man covers a distance of 675 km. His speed for the first half is 80 kmph and for the remaining distance it is 120 kmph. What is his average speed for the entire distance ?**- 100 kmph
- 95 kmph
- 90 kmph
- 96 kmph
- None of these
**In what time a 435 m long train running at 58 kmph can cross a signal pole ?**- 7.5 sec
- 15 sec
- 27 sec
- 25 sec
- None of these
**a 145 mitre long train, running at a speed of 69 kmph overtakes another train which is running in the same direction at a speed of 35 kmph in 27 seconds. Find the length of the second train ?**- 145 m
- 255 m
- 110 m
- 150 m
- None of these
**If a car travels at 5/8th of it's original speed, it takes 12 minutes more time to cover a certain distance. Find the actual time it takes to cover that distance?**- 36 min
- 24 min
- 18 min
- 20 min
- None of these
**A man covers 220 km in 8 hours and another 300 km at an average speed of 60 kmph. Find the average speed of the man for the total distance ?**- 43.75 kmph
- 55 kmph
- 45 kmph
- 40 kmph
- None of these
**A boat covers 91 km upstream in 7 hours. If the speed of the current of the stream is 4 kmph, find the speed of the boat ?**- 9 kmph
- 5 kmph
- 17 kmph
- 18 kmph
- None of these
**The speed of the boat in still water is 8 kmph. If it travels 12 kmph against the stream and 20 kmph along with the stream in the same time, what is the speed of the stream ?**- 10 kmph
- 2 kmph
- 4 kmph
- 8 kmph
- None of these
**Speed of a boat in still water is 12 kmph. It goes from a place A to another place B downstream and comes back from B to A upstream in 12 hours. If the speed of the current is 2 kmph, find the distance between A and B ?**- 36 km
- 72 km
- 70 km
- 45 km
- None of these
**A train crosses a bridge of length 290 metres in 27 seconds. Find the length of the train if it runs at 90 kmph speed.**- 385 m
- 270 m
- 245 m
- 675 m
- None of these
**A man travels with a speed 1 kmph less than his usual speed and reaches his home in 9/8th of actual time. What is his actual speed ?**- 9 kmph
- 12 kmph
- 15 kmph
- 10 kmph
- None of these
**A man goes round a circular track 7 times in 42 minutes. If the diameter of the circle is increased to 5 times the original diameter, what is the time required by the man to go round the new track once at the same speed ?**- 35 min
- 30 min
- 5 min
- 15 min
- None of these
**A boat covers a distance of 44 km down stream or a distance of 28 km upstream taking 4 hours each. Find the speed of the boat in still water ?**- 4 kmph
- 9 kmph
- 18 kmph
- 4.5 kmph
- None of these
**A man goes from his house to office in a car. If his speed is 60 kmph, he reaches his office 3 minutes late however if his speed is 80 kmph he is early by 5 minutes. Find the distance between his house and office.**- 32 km
- 25 km
- 60 km
- Can't be determined
- None of these
**A car takes 5 hours to cover a distance of 240 km. What should be the speed to cover the same distance in 4 hours ?**- 40 kmph
- 30 kmph
- 60 kmph
- 45 kmph
- None of these
**A driver was supposed to drive at a uniform speed to cover a distance of 180 km. He was 54 minutes late. To cover this lost time, he had to increase the speed by 10 kmph. What is the original speed ?**- 60 kmph
- 35 kmph
- 40 kmph
- 50 kmph
- None of these
**Speed of a boat is 7 kmph. It goes to a certain place downstream and comes back in 21 hours. If the speed of the current is 3 kmph, find the distance till that place ?**- 60 km
- 75 km
- 40 km
- 90 km
- None of these
**Gopal travels a certain distance. He travels for 15 minutes at the rate of 45 kmph in a car then travels for 15 minutes in a train at a speed of 75 kmph and another 15 minutes in a bus at the rate of 30 kmph. Find his average speed for the whole journey ?**- 43.5 kmph
- 65 kmph
- 50 kmph
- 70 kmph
- None of these
**A train crosses a bridge of length 800 m in 100 seconds and a platform of length of 400 m in 60 seconds. Find the length of the train ?**- 80 m
- 200 m
- 100 m
- Can't be determined
- None of these
**Two trains start from two stations A and B towards each other at 8 AM with speed 65 kmph and 80 kmph respectively. If they cross each other at 4 PM, what is the distance between A and B ?**- 1160 km
- 1250 km
- 1325 km
- Can't be determined
- None of these
**A boat covers 60 km distance downstream or 36 km distance upstream in the same time. If the speed of the current is 3 kmph, find the speed of the boat ?**- 48 kmph
- 12 kmph
- 16 kmph
- 15 kmph
- None of these

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Statutory Warning for the speed of 96 Kmph ? LOL ........ you people are so funny . I liked the way you teach things :)

ReplyDeleteplz provide problems on profit and loss

ReplyDeleteAnswer of 20th question should be 12 km/hr.

ReplyDeletePlz correct me if I am wrong.

Shivani Mam, Kindly check the answers of Ques 7 and 20. I think the answer of ques no. 7(3) and 20 (2) else all are correct. Answered 18/20. Thank you.

ReplyDeleteplease solve q.13

ReplyDeleteAs we know, time= dist./speed

ReplyDeleteSo, d/60= (t+3/60) eqn...1 (3/60 because we need to convert in hrs.) and t is the usual speed and hence he reaches office late so (t+3/60) hrs.

d/80= (t-5/60) eqn...2

60(t+3/60)= 80(t-5/60)

solving t=29/60 hrs.

Put the value of t in any one of the above equation:-

d= 60(29/60+1/20)

d= 29+ 3= 32 km.

in ques no. 7.. 12 and 20 should be in km not kmph

ReplyDeletehow to solve qus 4..pls explain...

ReplyDeleteThanks Maitri.Now i realise i can't qualify ibps po.

ReplyDeleteyeah...ans for question no.7 is 4kmph

ReplyDeletesomebody explain Q.15

ReplyDeleteThanks in advance

d=st

ReplyDeletehere s inversly propertonal to t

now let initial speed s1=s

final speed S2=5/8S

initilal tymT1=t

as it takes 1. mins more so T2=t+12

now applying formula S1/S2=T2/T1

S/(5/8)S=t+12/t

solving the equn t=20

here diff between time period is 54 min=54/60 hr

ReplyDeletenow d= st

t=d/s

let actuall speed is s

and increased speed is s+10

now t1-t2 =54/60

180/s -180/s+10 =54/60

solving s=-50 and 40

as speed cant be negative so s= 40

here diff between time period is 54 min=54/60 hr

ReplyDeletenow d= st

t=d/s

let actuall speed is s

and increased speed is s+10

now t1-t2 =54/60

180/s -180/s+10 =54/60

solving s=-50 and 40

as speed cant be negative so s= 40

explain qno19

ReplyDeletecheck the question no 7. i think it is not kmph. it may be 12 km and 20 km..

ReplyDeletethe trains left from oppsite diren so the reletive speed Rs=65+80=145

ReplyDeleteniw they left8am and crossed at 4 so total tym taken by them 8 hr

so appkying formula t=d/Rs

8=d/145

d=1160

yes it should be km

ReplyDeletethanks a lot.........

ReplyDeleteanswer of question 20 will be 12,plz check

ReplyDeleteanswer for ques no - 20 is 12 kmph

ReplyDeleteno problem bro

ReplyDeletethanx soooooooooooo muchh............:)

ReplyDeleteit is well useful for me madam////thanks a lot

ReplyDelete12 th question explanation lo 4(B+C)=44=>B+C=11

ReplyDelete13th question (product of speeds/diff b/w speeds)xdiff b/w time

ReplyDelete=>(80x60)/(80-60)x((5-(-3))/60)

=>(80x60/20)x(8/60)=>ans=36