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**here**and try to solve on your own before checking these solutions. Happy Reading.

**1.**Average Speed = 2XY / (X+Y)

=> (2 x 80 x 120) / (80 + 120)

= 96 kmph

**2.**Distance = 435 m,

Speed = 58 kmph = 58 x (5/18) mps

Time = Distance / Speed

=> 435 / ((58 x (5/18)) = (435 x 18) / (58 x 5) = 27 sec

**3.**Let the length of the second train be "X" metres.

Distance = 145 + X

Time = 27 sec

Speed = 69-35 = 34 kmph (Same direction)

=> 34 x (5/18) mps

145 + X = 34 x (5/18) x 27

=> X = 255 - 145 = 110

**4.**Let the actual speed be "S" kmph and time be "t" hours

So,

S.t = (5/8) . S . ((t+(12/60))

=> S = (1/3) x 60 = 20 minutes

**5.**Average speed = Total Distance / Total Time

=> (220+300) / ((8 hours + (300 km / 60 kmph)) = 520 km / (8+5 hours)

= 520 km / 13 hours = 40 kmph

**6.**Speed = 91 km / 7 hours = 13 kmph

Boat Speed - Current Speed (Upstream) = 13 kmph

= Boat Speed - 4 = 13

=> Boat Speed = 13+4 = 17 kmph

**7.**Let the speed of the stream be "X" kmph

Time to travel against stream = 12 / (8-X) hours

Time to travel along with the stream

= 20 / (8+X) hours

So, 12/(8-X) = 20 / (8+X)

=> 12 (8+X) = 20 (8-X)

=> X = 2 kmph

**8.**Let the distance between A and B be "X" km

So, (X/(12+2) + (X/(12+2)) = 12 => X = 70

**9.**Let the length of the bridge be "X" km

So, (290 + X) m = 90 x (5/18) mps x 27 sec

=> 290 + X = 675 m => X=385 m

**10**. Let the original speed be "S" kmph and original time be "T" hours

Distance = S.T

So, S.T = (S-1) x (9/8) T

=> S = 9 kmph

**11.**Time taken to complete one round is 42/7 = 6 min

if the diameter increases 5 times, the circumference also increases 5 times

So, New time taken to complete one round is 5 x 6 = 30 minutes

**12.**Let the speed of the boat be "B" kmph and speed of the current be "C" kmph

So, 4 (B-C) = 44 => B+C = 11

4 (B-C) = 28 => B - C = 7

Solving both the equations, B = 9 kmph

**13.**Let the distance between his house and office be "X" km

So, (X km / 60 kmph) - (X km / 80 kmph) = ((5-(-3)) / 60 hours

=> X = 32 km

**Shortcut Technique :**

Required Distance = (Products of Speeds / Difference of Speeds) x Difference in Time

=> ((80 x 60) x (80+60)) x (8/60) = 32 km

**14.**Here original time is not required

Required speed = (240 km / 4 hours) = 60 kmph

**15.**Let the original speed is "X" kmph

So, (180/X) - ((180 / (X+10)) = 54 / 60

=> X = 40 kmph

**16.**Let the distance between the places be "X" km

=> ((X / (7+3)) + ((X / (7-3)) = 21 => X = 60 km

**17.**When time is same in each case, the average speed will be the simple average of the speeds

=> Average Speed = ((45 + 75 + 30) / 3) = 150 / 3

= 50 kmph

**18.**Let the length of the train be "X" metres

=> ((80 + X) / 100) = ((400+X)/60)

=> X = 200 m

**19.**Time for meeting each other is 8 hours

The relative speed is 65 + 80 = 145kmph (opposite direction)

So, Distance between A and B

= 145 x 8 = 1160 km

**20.**Let the speed of the boat be "B" kmph

=> ((60 / (B+)) = ((36 / (B-3))

=> B = 12 kmph

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ReplyDeletemaths(simplification(5),approximation(5),number series(5),DI(15))

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focus mainly on this u will get good score...all the best

ReplyDeletethanks shivani mam....check q no 8 --> x/12-2

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ReplyDeletethanks na.....

ReplyDeletehow to solve seating arrangement sir ? plz tell me

ReplyDeletehow many such pairs of letters are there in the word INTEREST each of which has as many letters between them in the word as in the English alphabetical series? till now i didn't understand tis type of question plz explain the solution sir....

ReplyDeleteMore explanation needed on ques num 4

ReplyDeleteU hv to findout the letter pairs which hv the no of letters betweeen them in the alphabetical series equal to the no of letters between them in the word given.for ex here let us take the pair IN, here no letter between I And N but in alphabetical series we hv j k l m =4 letters between them so this pair doesn't satisfy the given condition. Now lets take the pair ST here no letter between them and in alphabetical series also we hv no letters between S and T so this pair satisfy our condition , similarly find such pairs in the given word.

ReplyDeletei got minimum three pairs in the word ... is it correct mam....

ReplyDeleteHi SuganyaNS,

ReplyDeleteIn the exam write alphabets and their corresponding number in the rough sheet.This can help you in solving this type of question.

a -1

b-2

z-26

For ex INTER i-9 n-14 t-20 e-5 r-18

Here

count the numbers which u feel nearest. 18 and 20 are near to each other.

t and r has the same letters.

18,19,20

for quant try to solve di first

ReplyDeletedo practice as many sets as u can

try to keep you score above 25

in reasoning

avoid puzzles first

sove the rest

in the last if you get time finds puzzle easy go for it

25+ is a good score for po

all the best

No there r four such pairs TR ST NS NT, u hv to look in backward direction also

ReplyDeleteHi SuganyaNS,

ReplyDeletePlease solve more seating arrangement this way u can get practice it.

But my suggestion is don't attend seating arrangement if you are not confident this is because po seating arrangement will be high level and it takes more time solving.

But if your confident and practiced enough in solving previous year po questions you can attempt it.

Very Simple ANS Is 4 pair NS, NT, ST, RT

ReplyDeleteI N T E R E S T

9 14 20 5 18 5 19 20

thanks na.....

ReplyDeletethanks mam... SEASON... in this word . NO,NS,AS

ReplyDeleteThere are four pairs.

ReplyDelete1)N-S(in INTEREST- TERE- 4 letters between N & S, in alphabet OPQR- 4 letters)

2)N-T(in INTEREST- TERES- 5 letters between N & last T, in alphabet OPQRS- 5 letters)

3)T-R(in INTEREST- only E- 1 letter between 1st T & R, in alphabet only S- 1 letter)

4)S-T(in INTEREST- no letter between S& T, in alphabet no letter between S & T).

The answer is SO, SN, ON.

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thanks na....

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ReplyDeleteThanks........

ReplyDeleteHi SUgan,

ReplyDeleteI ll give u a tip just try to attempt the questions u know and don't answer if u r not sure.

First try to clear Sectional cut off and then overall cutoff.

Each section try to answer 15 correctly.

And then go for your strong section.

First attempt computer then GA and English.

In english only attempt sentence arrangement,error correction,fill in blanks. Total 20.

For the above three section allot 45 mins.

Remain two section use the 1hr 15 mins.

Follow this u ll surely get enough time and can clear the exam.

All the best.

Hi sugan,

ReplyDeleteVisit the link download the previous year question papers and solve 2013 year question paper seating question no 7.

http://www.gr8ambitionz.com/2014/09/ibps-po-cwe-iii-previous-paper-2013-pdf-download.html

Sorry solve 2012 question paper. qno 22

ReplyDeletemine is madurai kln college.... plz give me one seating arrangement question na i'll solve it nd tell the answer .. rectify my errors na....

ReplyDeleteThere are eight friends S,T,U,V,W,X,Y, and Z sitting around a circular table facing the centre and playing cards but not necessarily in the same order. All of them have a favourite card among these eight cards. Out of these eight cards, four are Kings and four are Queens of spade, club, diamond and heart.

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plz tell me how to solve this problem.......

There are eight friends S,T,U,V,W,X,Y, and Z sitting around a circular table facing the centre and playing cards but not necessarily in the same order. All of them have a favourite card among these eight cards. Out of these eight cards, four are Kings and four are Queens of spade, club, diamond and heart.

ReplyDeleteS like the Queen of spade and is not an immediate neighbour of the one who likes the King of club. The one who likes the Queen of diamond sits on the immediate left of T, who likes the Queen of club. U likes the King of club and sits third to the left of W. The one who likes the king of spade and the one who likes the Queen of diamond are immediate neighbours of each other but both of them are the neighbours neither of W nor of U. The one who likes the King of diamond and the one who likes the Queen of spade are immediate neighbours of each other. Neither W nor V likes the king of diamond. Only X sits between the one who likes the Queen of diamond and the who likes the Queen of heart, Y sits third to the left of the person who likes the king of diamond.

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Intially I had the problems of shivering, tension. when i read question i was just reading it not understanding it because of tension, so it takes more time. As a result in 1 Big exam became a big flop ie marks was too disappointing. After that i changed my strategy. I will mail you if you provide me your ID because it takes some space. Don't know whether it will work for you. But i too was in similar situation like you then. Now atleast am able to pass written exams well

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