New Pattern Time & Work Problems with Solutions for Bank Exams 2019

New Pattern Time and Work Practice Problems

Directions (1-2) : One day earning of P, Q and R together is Rs.1026 to do a work. ‘P’ earns more than R which is same as ‘R’ earns more than ‘Q’. Efficiency of R and Q is 19 : 18.

1. Find the amount earned by R and P together in 5 days to do the same work?

1. Rs. 3620
2. Rs. 3430
3. Rs. 3510
4. Rs. 3310
5. Rs. 3710

2. S, who’s efficiency is average of efficiency of P and Q, can complete a work in 36 days. If P, Q and R work together, and complete that work then find the total wage of Q

1. Rs. 3888
2. Rs. 4104
   
3. Rs. 4320
4. Rs. 3666
5. Rs. 4520

3. (X+4) men can complete a work in 2X days while (X+12) women can complete same work in (X+8) days. If ratio of efficiency of men to women is 5 : 4 then find in how many days 12 men and 15 women together can complete the same work ?

1. 32 days
2. 16 days
3. 48 days
4. 64 days
5. 80 days

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SBI PO and Clerks Special 2018 : Quantitative Aptitude Practice Test

1. A shop keeper sells milk which contains 5% water. What quantity of pure milk should be added to 2 liters milk (containing 5% water) so that proportion of water becomes 4% ? 
1. 100 ml 
2. 250 m1
3. 400 ml 
4. 350 ml 
5. None of these 
2. A and B started a business in partnership investing Rs. 20,000 and Rs. 15,000 respectively. After six months C joined them with Rs. 20,000. What will be B's share in the total profit of Rs. 25,000 earned at the end of two years from the starting of the business ?
1.  Rs. 9,000
   
2. Rs. 10,000 
3. Rs. 7,500 
4. Rs. 9,500
5. None of these 
3. What approximate value should come in place of the question mark (?) in the following equation ?                   158.25 x 4.6 + 21% of 847 + ? = 950.93 
1. 35 
2. 40
3. 25 
4. 50 
5. 45 
4. The average of the first and the second of three numbers is 15 more than the average of the second and the third of these numbers. What is the difference between the first and the third of these three numbers ?
1. 15 
2. 45
3. 60 
4. Data inadequate
5. None of these 

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Mensuration Practice Problems for SBI POs and Clerks

Mensuration means measurement. It is being done in our life in many situations. For example, Length of cloth we need for stitching, the area of a wall which is being painted, perimeter of a rectangular plot to be fenced, quantity of water needed to fill the tank, etc. For these kinds of activities, we are doing measurements for further needs.

Here, we cover three areas, those are

1. Perimeter
2. Area and
3. Volume

Try to solve these questions on your own and check with the answers given below the questions. You can check detailed explanations of these answers from here. Happy Reading :)

1. The area of a rectangular plate is 236.25 sq.cm. If the length of the plate is 17.5 cm, find the perimeter of the plate.
1. 65 cm
2. 52 cm
3. 62 cm
4. 67 cm
5. None of these
2. The breadth of a rectangular plot is 75% of its length. If the perimeter of the plot be 1050 m, what is its area ?
1. 12500
2. 57500
3. 62500
4. 67500
5. None of these
3. In measuring the sides of a rectangle, one side is taken 10% in excess, and the other 5% in deficit. What is the change in its area as a percentage ?
1. 1.5%
2. 4.5%
3. 2.5%
4. 5%
5. None of these
4. How many tiles of 20 cm length and 10 cm width are required to pave the floor of a room 8 m long and 5 m wide ?
   
1. 2100
2. 1500
3. 2500
4. 2000
5. None of these
5. The circumference of two circles is 88 metre and 132 metre respectively. What is the difference between the area of the larger circle and the smaller circle ?
1. 440 sq.m
2. 510 sq.m
3. 770 sq.m
4. 225 sq.m
5. None of these
6. A solid metallic spherical ball of radius 7 cm is melted down and recast into small cones. If the diameter of the base of the cone is 14 cm and the height is 2 cm, find the number of such cones can be made ?
1. 14
2. 28
3. 7
4. 12
5. None of these
7. A hall is 10 metres long and 8 metres wide. What will be the cost of carpenting the room if 0.5 metres of space is left around the room ? The rate of 0.25 metre wide carpet is Rs. 20 per metre.
1. Rs. 1560
2. Rs. 2520
3. Rs. 1875
4. Rs. 5040
5. None of these
8. A square field has an area of 50625 sq. m. Find the cost of fencing around it at Rs. 15 per metre. 
1. Rs. 12500
2. Rs. 17500
3. Rs. 13500
4. Rs. 16250
5. None of these
9. Cost of fencing a circular plot at the rate of Rs. 12 per metre is Rs. 2,640. What will be the cost of carpeting the floor of the plot at the rate of Rs. 85 per square metre ?
1. Rs. 3,25,250
2. Rs. 3,22,350
3. Rs. 3,27,250
4. Rs. 3,25,750
5. None of these
10. A circle and a rectangle have the same perimeter. The sides of the rectangle are 18 cm and 26 cm. What will be the area of the circle ?
1. 88 cm²  
2. 1250 cm² 
3. 154 cm²
4. 128 cm²
5. None of these 
11. A circular garden has a 7 m wide road around the boarder. Find the cost of leveling the road at Rs. 5 per square meter if the radius of the inner circle is 21 m ?
1. Rs.3490
2. Rs. 5390
3. Rs. 2930
4. Rs. 5695
5. None of these 
12. The lateral surface area of a cylinder is thrice the area of its base. Find the ratio of it's height and the base radius ?
1. 2:3
2. 2:5
3. 3:2
4. 4:9
5. None of these 
13. Two cubes have their volumes in the ratio 8:27. Find the ratio of their surface areas. 
1. 2:3
2. 4:9
3. 16:81
4. 8:9
5. None of these  
14. A horse is tied with a 14 m long rope. How much ground will it be able to graze ?
1. 125 Sq. m
2. 275 Sq. m
3. 625 Sq. m
4. 675 Sq. m
5. None of these 
15. Find the length of the longest stick that can be placed in a room of 12 m long, 9 m broad and 8 m high. 
1. 21 m
2. 29 m
3. 20 m
4. 17 m
5. None of these  
16. A field is 375 m long and 40 m broad. A tank 30 m long, 20 m broad and 12 m deep is dug in the field and earth taken out of it and is spread equally over the field. How much is the level of field raised ?
1. 48 cm
2. 0.5 cm
3. 25 cm
4. 50 cm
5. None of these  
17. A rectangular field of 60-metre length and 40 metres wide is to be surrounded by a road 5 metre wide. If the cost of making 1 square metre road is Rs. 500, what would be the cost of entire road ?
1. Rs. 6,25,000
2. Rs. 5,55,000
3. Rs. 5,50,000
4. Rs. 5,67,500
5. None of these  
18. A room is 7.5 m long, 5.5 m broad and 5 m high. What will be the expenditure in covering the walls by paper 40 cm broad at the rate of 75 paise per metre ?
1. Rs. 245.25
2. Rs. 243.75
3. Rs. 275.50
4. Rs. 275.45
5. None of these 
19. The length and breadth of a rectangle increased by 20% and 10% respectively. How much percent will its area be increased ?
1. 25%
2. 30%
3. 40%
4. 32%
5. None of these  
20. 7 cm radius and 28 cm height solid metallic cylinder is melted and recast into small spherical balls of 7cm radius. Find the number of cubes that can be made ?
1. 12
2. 5
3. 3
4. 6
5. None of these 

Check Detailed Solutions of these problems from here

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Quantitative Aptitude : Partnership Problems with Solutions - Lesson 2

Hi friends, I am Aindree. In our previous lesson, we have learnt the Introduction of Partnership topic of Aptitude Section. Today we shall see some practice problems with explanations. Happy Reading :)

Note : Before reading these examples, please read the Introductory Lesson 1 from here for better understanding. Thank you :)

Example 6 : A, B and C investment in a partnership in the ratio of 5 : 6 : 8. Ratio of their profit is 5 : 3 : 12. Find the ratio of time for their investment ?

Solution :

Required Ratio = (5/5) : (3/6) : (12/8)

= 1 : (1/2) : (3/2)

= 2 : 1 : 3

Example 7 : Three people A, B and C invested money in a partnership in the ratio of 4 : 2 : 8 ratio of their time of investment is 3 : 3 : 2. What is the ratio of their profit ?

Solution :

Required ratio = 4 x 3 : 2 x 3 : 8 x 2

= 12 : 6 : 16

= 6 : 3 : 8

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Quantitative Aptitude Practice Test for Bank and Insurance Exams (with Explanations)

Quantitative Aptitude Practice Test

1. The number of students studying Arts, Commerce and Science in an Institute in the year 2002 were in the ratio 8 : 5 : 6 respectively. If the number in the three disciplines increased by 30%, 20% and 60% respectively in the year 2003, what was the new respective ratio ?

1. 9 : 7 : 8
2. 26 : 15 : 24 
3. 27 : 13 : 12 
4. Can't be determined 
5. None of these 

2. In how many different ways can the letters of the word 'HOUSING' be rearranged ? 

1. 120
   
2. 720 
3. 2150 
4. 2520 
5. None of these 

3. A boy walks 14m to cross a square field diagonally. What is the area of the square?

1. 78 sqm 
2. 120 sqm 
3. 118 sqm 
4. Can't be determined 
5. None of these 

4. 8 women can complete a work in 10 days and 10 children take 16 days to complete the same work. How many days will 10 women and 12 children take to complete the work ? 

1. 5
2. 7 
3. 3 
4. Can't be determined 
5. None of these 

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Aptitude : Percentage Problems with Explanations - Introduction

Hi friends, thank you so much for the great response to my yesterday's post on Partnership problems. Today I am posting the introduction and problems on Percentage. In this post i am covering the basic details of percentage, from our next post we shall cover the problems with Higher difficulty level. Happy Reading :)

Percentage Problems Introduction

A fraction with denominator 100 is called percentage. Numerator of that fraction is called rate percent.

The term percent means per every 100.

50 percent means 50 out of 100.

The symbol % is used to denote percent.

Ex : 20%, 35%, 80% etc.

Percent to fraction : To convert percent into fraction, divide the percent by 100.

Ex : 25% = 25/100 = 1/4

Fraction to percent : To convert fraction into percent, multiply the fraction by 100. 

Ex : 1/5 = (1/5) x 100 = 20%

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Partnership Problems with Shortcut Methods - Introduction

Hi friends, I am Aindree. An SBI PO aspirant. Here I am going to share Aptitude notes which I have been using for my preparation. I hope this will be helpful for my fellow aspirants. Happy Reading :)

Partnership Introduction 

When two or more persons start a business jointly and share the profit or loss threof in an agreed proper portion, it is known as partnership business and the persons carrying on such business are called Partners. Generally partners share the profit or loss in the ratio of the capitals invested by them. Partnership may be of two types. They are,

1. Simple
2. Compound

Let's have a detailed look about these types of Partnerships.

Simple Partnership : When the capitals of the partners are invested for the same time, then this type of partnership is called simple partnership. In such a case, the profit or loss is distributed in proportional to the capital invested.

Compound Partnership : When the capital, which is equal or unequal, of the partners, is invested for different times, this type of partnership is called compound partnership. In such a case the profit or loss is distributed in proportional to the products of the capital and the periods of their investment.

An Important formal for Solving the Problems of Partnership is 

(Capital of A x time invested in capital of A) / (Capital of B x time invested by Capital of B) = Profit of A / Profit of B

Working Rule -

1. If the ratio of investment by three persons is a : b : c and ratio of time invested in their capital is x : y : z then the ratio of their profit will be ax : by : cz.
2. If the ratio of investment by three persons is a : b : c and ratio of their profit is p : q : r then, the ratio of time invested in their capital will be p/a : q/b : r/c

Now let's have a look at some examples.

Example 1 : A, B and C enter into partnership. A contributes one-third of the capital while B contributes as much as A and C together contribute. If the profit at the end of the year amounts to Rs. 840 what would each receive ?

Solution :

As A contributes one-third of the capital

=> A's profit = 840/3  =Rs. 280

Now as B contributes as much as A and C

So profit of B = Profit of A + Profit of C =  Rs. 280 + Profit of C

=> Profit of B - Profit of C = Rs. 280

and Profit of B + Profit of C = Rs. 840 - Rs. 280

adding 2 Profit of B = Rs. 840

Profit of B = Rs. 420

Hence profit of C = 840 - 420 - 280

= Rs. 140

Example 2 : A is working and B is sleeping partner in a business. A puts Rs. 5,000 and B puts in Rs. 6,000. A receives 12 1/2% of the profit for Managing the business and the rest is divided in proportion of their capitals. What does each get out of a profit of Rs. 880 ?

Solution :

The amount, which A receives for managing the business = 12 1/2 % of Rs. 880

= (25 / (2 x 100)) x 880 = Rs. 110

The amount left = 880 - 110 = Rs. 770

The amount left is to be divided in the ratio = 5,000 : 6,000 = 5:6

Out of the amount left, A's share  =  (5/11) x 770 = Rs. 350

Out of the amount left, B's share = (6/11) x 770 = Rs. 420

Total share received by A = 110 + 350 = Rs. 460

Share received by B = Rs. 420

Example 3 : A and B enter into a partnership. A contributes Rs. 5000 while B contributes Rs. 4000. After 1 month B withdrawn 1/4 part of his contribution and after 3 months from the starting A puts Rs. 2000 more. When B withdraws his money at the same C also joins them with Rs. 7000. If at the end of 1 year there is a profit of Rs. 1218, what will be share of C in the profit ?

Solution :

Since the contribution of three partners are different and their times also differ. Therefore, their contributions should be converted for equal durations. For this, contribution is multiplied by time.

=> Contribution of A = Rs, 5000 for 12 months + Rs. 2000 for 9 months

Contribution of A for 1 month = 5000 x 12 + 2000 x 9

= 60000 + 18000 = Rs. 78000

Contribution of B = Rs. 4000 for 1 month + 3/4 of Rs. 4000 ofr 11 months

=> Contribution of B for one month = 4000 x 1 + 3000 x 11

= 4000 + 33000 = Rs. 37000

=> Contribution of C = Rs. 7000 for 11 months

Contribution of C for 1 month = 7000 x 11 = Rs. 77000

=> Ratio in their contributions = 78000 : 37000 : 77000

= 78 : 37 : 77

=> Sum of their ratios = 78 + 37 + 77  = 192

=> Share of C in the profit  = (77 x 1218) / 192  = Rs. 488.47

Example 4 : Alok started a business by investment of Rs. 90000 after 3 months Pranav joned him with an investment of Rs. 120000. If they had a profit of Rs. 96000 after 2 years then what is the difference in the shares of two ?

Solution :

Alok's investment for 1 month = 90000 x 24 = 2160000

Pranav's investment for 1 month = 120000 x 21 = 252000

=> Ratio of their investment =  6:7

=> Required difference  = ((7-6) x 96000) / (6+7)

= Rs. 7384

Example 5 : A, B and C started a business in partnership. A invested Rs. 25 lacks and after 1 year he invested Rs. 10 lacks more. B invested Rs. 35 lacks in the beginning and withdrew Rs. 10 lacks after 2 years. C invested Rs. 30 lacks. What is the ratio of their profit after 3 years ?

Solution :

A's investment = 25 x 3 + 10 x 2  = Rs. 95 lacks

B's investment = 35 x 2 + 25 x 1  = Rs. 95 lacks

C's investment = 30 x 3  = Rs. 90 lacks

Ratio of their investment = 19 : 19 : 18

Ratio of their profit = 19: 19 : 18

(because time period is same, i.e., for 3 years)

That's all for today friends. In my next lesson I will try to cover more examples higher difficulty level along with examples. All the Best :)

shared by Aindree Mukherjee

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Permutations & Combinations - Lesson 2

Hi friends, in my previous introductory lesson of Permutations & Combinations, we have learnt some fundamentals of Permutations & Combinations. Today we shall learn Lesson 2 of Permutations & Combinations. Before reading this, please read the Lesson 1 from HERE.

Circular Permutations

When we consider the arrangements of objects in a line, such permutations are known as linear permutations instead of arranging the objects in a line, if we arrange tem in the form of a circle, we can call them circular permutations.

In circular permutations, objects are arranged along the circumference of a circle. Here, there is neither a beginning nor an end. We fix the position of one objects and then arranger the remaining (n-1) objects in all possible ways.

This can be done in (n-1)!

Note :

1. The number of circular permutations of n different objects = (n-1)! 
2. The number of ways in which n person can be seated around a circular table is (n-1)! 

SOLVED EXAMPLES

1. In how many can 10 businessmen sit around a round table such that 2 businessmen
(i) Always sit together ii) never sit together 

Sol.

(i) If 2 businessmen always sit together we can consider them to be one unit. Thus, we have to arrange 9 units in a circle. This can be done in (9 — 1)! = 8! ways.

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Time and Work, Pipes and Cisterns Online Practice Tests

Friends, here are some practice problems on Time and Work, Pipe and Cisterns for upcoming competitive exams. Try to solve these on your own and check with the answers given below. You will get detailed solutions with explanations soon. 

Time and Work Practice Problems :

1. Two persons Kamal and Vimal together can complete a piece of work in 9 days. Vimal alone can do that work in 36 days. In how many days can Kamal alone can complete that work ?
1. 16 days
2. 18 days
3. 12 days
4. 24 days
5. None of these
2. A and B can do a work in 20 days and 12 days respectively. The worked together on it for some time. C joins and finishes in 2 days. If C can do the total work in 10 days, how long did A and B together work ?

1. 6 days
2. 8 days
3. 10 days
4. 5 days
5. None of these
3. Rajesh is thrice as good workman as Manish and therefore able to finish a work 12 days less than Manish to finish a piece of work. In how many days they can complete if they work together ?
1. 8 days
2. 4 days
3. 16 days
4. 4(1/2) days
5. None of these
4. A, B and C can do a piece of work in 30 days, 24 days and 40 days respectively. They started working together but C left four days before the completion of the work. In how many days was the work finished ?
1. 5 days
2. 11 days
3. 12 days
4. 8 days
5. None of these
5. 72 men can complete a piece of work in 48 days. In how many days can 54 men finish the same work ?
1. 46 days
2. 68 days
3. 32 days
4. 64 days
5. None of these
6. A can finish the work in 5 days and B in 6 days. In what time they can complete it working alternatively starting with A ?
1. 5(3/5)
2. 5(2/5)
3. 5(1/2)
4. 5(1/3)
5. None of these
7. If 2 men and 3 boys can do a piece of work in 8 days and 3 men and 2 boys can do it in 7 days. In how many days will 5 men and 4 boys take to complete it ?
1. 4 days
2. 6 days
3. 7 days
4. 3 days
5. None of these
8. A contractor agrees to do a work in 36 days and employs 16 men. After 20 days he finds that only 40% of the work is finished. In order to complete the work in the stipulated time how many more men he has to recruit ?
1. 30
2. 16
3. 14
4. 12
5. None of these
9. A and B can do a piece of work in 12 days, B and C in 15 days and A and C in 20 days. In what time can A , B and C together can complete it ?
1. 5 days
2. 12 days
3. 20 days
4. 4 days
5. None of these
10. In a garrison provision is sufficient for 1200 soldiers for 30 days. But after 12 days 400 more soldiers joined the garrison. Find for how many days provision last for them ?
1. 15 days
2. 13.5 days
3. 12 days
4. 14 days
5. None of these
11. Ramu can do a certain job in 12 days. Raju is 60% more efficient than Ramu. In how many days can Raju do the same piece of work ?
1. 15 days
2. 19(1/5) days
3. 7(1/2) days
4. 8 days
5. None of these
12. 15 men would finish a piece of work in 60 days. If at the end of every 10 days, 5 additional men are employed, in how many days will it be finished ?
1. 40
2. 15
3. 30
4. 50
5. None of these
13. A man and a boy working together can do a certain amount of work in 30 days and are paid Rs. 1440. If the efficiency ratio of the man and the boy is 9:7, find the daily wages of the boy ?
1. Rs. 24
2. Rs.28
3. Rs.35
4. Rs.21
5. None of these

Pipes and Cisterns Practice Problems

1. A pipe can fill a tank in 16 min and leak can empty the full tank in 24 minutes. If both are open simultaneously, in what time can the tank be filled ?
1. 8 min
2. 28 min
3. 32 min
4. 48 min
5. None of these
2. Two pipes A and B fill a tank in 12 and 18 minutes respectively. Both pipes being opened, find when the first pipe must be turned off so that the cistern may be filled in 12 minutes ?
1. 6 min
2. 15 min
   
3. 9 min
4. 10 min
5. None of these
3. A tank can be filled by two taps in 6 hours and 9 hours respectively. The first tap was opened at 8 AM., and the second at 9 AM. At what time will the tank be filled ?
1. 11 AM
2. 1 PM
3. 12 AM
4. 2 PM
5. None of these
4. Two pipes A and B can fill a tank in 5 hours and 20 hours respectively. If both the pipes opened, due to a leakage it takes 30 minutes more to fill the tank. If the tank is full, how long will it take for the leakage alone to empty the tank ?
1. 4.5 hours
2. 9 hours
3. 36 hours
4. 24 hours
5. None of these
5. Three pipes A, B and C can fill a tank in 6 hours. After working 2 hours, C is closed and A and B fill it in another 7 hours. In how many hours will C along can fill the tank ?
1. 9 hours
2. 14 hours
3. 16 hours
4. 8 hours
5. None of these
6. A tank is filled by a tap in 3.5 hours. Due to a leak in the bottom of the tank , it takes half an hour longer to fill the tank. If the tank is full how long will it take the leak to empty it ?
1. 7.5 hours
2. 28 hours
3. 32 hours
4. 34 hours
5. None of these
7. Two pipes A and B can fill a cistern in 20 minutes and 30 minutes respectively. A drain pipe C can  remove 40 liters of water per minute. If all the three pipes are opened, it takes one hours to fill the cistern. What is the capacity of the cistern ?
1. 900 liters
2. 750 liters
3. 500 liters
4. 600 liters
5. None of these

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Permutations & Combinations Problems with Shortcut Methods - Introduction

Hi friends, today we shall learn the basics of Permutations & Combinations of Aptitude Section. Happy Reading :)   

Factorial Notation

Let n be a positive integer. Then the continued product of first 'n' natural numbers i.e.,

1 x 2 x 3 x 4 x ..... x (n-1) x n is known as 'n' factorial is denoted by n!

Also as per definition 0! = 1

Note : When 'n' is factorial or a negative n! is not defined.

Hence n! = 1 x 2 x 3 x ....... x (n - 2) x (n - 1) x n

Fundamental Principle

Let's consider the following example.

A person wants to travel by a car, bus, train or an aero plane while traveling from Hyderabad to Nagpur. But for the return journey he can travel in any these manners except the aero plane. In how many ways can the man complete his journey ?

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Simple & Compound Interest Problems with Shortcuts

SIMPLE INTEREST AND COMPOUND INTEREST

The money borrowed or lent out for a certain period is called the principal or the sum.

Simple Interest

When a sum of money is borrowed for a period, an extra amount has to be paid along with the borrowed money. The fixed rate of the extra amount is called interest.

The interests are of two types : Simple Interest and Compound Interest.

Simple interest is the interest pa-id at the end of the period. Or if the interest on a sum borrowed for certain period is reckoned uniformly, then it is called simple interest.

Let Principal = P, Rate = R% per annum (p.a.) and Time = T years.


Then

Compound Interest

Compound interest is interest that is paid on both the principal and also on any interest from past years. It's often used when someone reinvests any interest they gained back into the original investment. For example, if a man got 15% interest on Rs.1000 investment, the first year and he reinvested the money back into the original investment, then in the second year, he would get 15% interest on Rs.1000 and the Rs.150 he reinvested. Over time, compound interest will make much more money than simple interest.

Important Formulae :

Let Principal = P, Rate of Interest = R% and Time = T years

Important Values (Shortcut Table) :

Some more important formulae :

1. To find compound interest for two years, when simple interest is given :

Compound Interest = Total simple interest + (Simple interest for one year x Rate of Interest)

2. If the difference between the compound interest and simple interest on a certain sum of money for 2 years at R% per annum rate is Rs.'D', then

3. If the difference between the compound interest and simple interest on a certain sum of money for 2 years at R% per annum rate is Rs. 'D',

4. If the difference between the compound interest and simple interest on a certain sum of money for 3 years at R% per annum rate is Rs. 'D', then 

5. If the difference between the compound interest and simple interest on a certain sum of money for 3 years at R% per annum rate is Rs.'D', then

PRACTICE QUESTIONS

1. What will be the compound interest on a sum of Rs.7200 at 5% p.a. in 2 years ?
1. Rs.841
2. Rs.738
3. Rs.793
4. Rs.812
5. Rs.694
2. What will be the compound interest on a sum of Rs.7500 at 4% per annum in 2 years ? (SBI 2012)
1. Rs.618
2. Rs.612
3. Rs.624
4. Rs.606
5. Rs.621
3. In how many years will Rs.4600 amount to Rs.5428 at 3% per annum simple interest ?
1. 3
2. 5
3. 6
4. 4
5. None of these
4. How much will a sum of Rs.7250 amount in a span of 2 years, at 6% per annum rate of compound interest? (Rounded off to the nearest integer) (SBI 2012)
1. Rs.8176
2. Rs.8146
3. Rs.8216
4. Rs.8190
5. Rs.8196
5. At what rate of simple interest will Rs.4200 amount to Rs.6216 in a span of 8 years? (SBI 2011)
1. 5
2. 3
3. 6
4. 4
5. None of these
6. At what rate of simple interest will Rs.4800 amount to Rs.6480 in a span of 7 years ?
1. 5
2. 6
3. 3
4. 4
5. None of these
7. How much will a sum of Rs.6300 amount in a span of 2 years, at 5% per annum rate of compound interest (Rounded off to the nearest interest) ?
1. Rs.6946
2. Rs.6876
3. Rs.6521
4. Rs.6790
5. Rs.6492
8. The difference between the C.I. and S.I. on a certain amount at 10% per annum for 2 years, compounded annually is Rs.372. Find the principal.
1. Rs.37,200
2. Rs.30,000
3. Rs.36,600
4. Rs.32,440
5. None of these
9. The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Rs.l. Find the principal.
1. Rs.600
2. Rs.625
3. Rs.630
4. Rs.640
5. Rs.664
10. Find the compound interest on Rs.64,000 at 5% per annum for 18 months, compounded half yearly ?
1. Rs.2,000
2. Rs.3671
3. Rs.4231
4. Rs.4921
5. None of these
11. A man gets a simple interest of Rs.1,000 on a certain principal at the rate of 5% per annum in 4 years. What compound interest will the man get on twice the principal in two years at the same rate? (Punjab & Sind Bank PO - 2010)
1. Rs.1,000
2. Rs.1,005
3. Rs.11,025
4. Rs.10,125
5. None of these
12. The simple interest accrued on an amount of Rs.22,500 at the end of four years is Rs.10,800. What would be the compound interest accrued on the same amount at the same rate of interest at the end of two years ? (IBPS 2011)
1. Rs.16,908
2. Rs.5,724
3. Rs.28,224
4. Rs.8,586
5. None of these

Solutions :

1. Sol: P = Rs.7200, R = 5%, T = 2 years

2. Sol : 

P = Rs.7500, R = 4%, T = 2 years

3. Sol : 

P = Rs.4600, A = Rs.5428

SI = 5428 - 4600 = Rs.828,

R = 3%,

T = ?

T = (100xSI) / PR = (100x828) / (4600 x 3) = 6 years


Ans: 3

4. Sol : 

P = Rs.7250, R = 6% p.a., T = 2 years

5. Sol :

P = Rs.4200,  A = Rs.6216, T = 8 years

S.I. = A - P = 6216 - 4200 = 2016


R =  (100 x SI) / PT

= (100x2016) / (4200 x 8) = 6% pa

Ans: 3

6. Sol : 

P = Rs.4800, A = Rs.6480, T = 7 years

S.I. = 6480 - 4800 = Rs.1680

R = (100 x SI) / PT

= (100 x 1680) / (4800 x 7) = 5%

Ans: 1

7. Sol :

P = Rs.6300, T = 2 years, R = 5%

8. Sol :

The sum (P) =

Ans : 1


9. Sol :

The sum (P) =

10. Sol :

P = Rs.64,000, T = 18 months

11. Sol :

12. Sol :

Ans: 2

Shared by Shravan Varma Gadhiraju

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4. 39%
5. None of these
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5. None of these
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