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**Data Interpretation Practice Test for SBI PO & Clerks Exams 2018**

**Directions (Q. No. 1 - 5): Study the following bar graph carefully to answer the questions.**

Marks obtained by five students in Physics and Chemistry

**Marks obtained by S in Chemistry is what percent of the total marks obtained by all the students in Chemistry ?**- 25%
- 28.5%
- 35%
- 31.5%
- 22%
**If the marks obtained by T in Physics were increased by 14% of the original marks, then what would be his new approximate percentage in Physics, when the maximum marks in Physics were 140 ?****Total marks obtained by T in both the subjects together is more than the marks obtained by :**- Q in Chemistry
- R in Physics
- S in Chemistry
- P in Physics
- R in both the subjects together
**What is the respective ratio between the total marks obtained by P in Physics and Chemistry together to the total marks obtained by T in Physics and Chemistry together ?**- 3 : 2
- 4 : 3
- 5 : 3
- 2 : 1
- None of the above
- What is the respective ratio between the total marks by Q and S together in Chemistry to the total marks obtained by P and R together in Physics ?
- 23 : 25
- 23 : 21
- 17 : 19
- 17 : 23
- None of the above

**Directions (Q. No. 6 -10) : Study the following bar-chart and piechart to answer the questions given below.**

Number of candidates (in thousand) who appeared for the SBI PO Exams from six different cities.

Percentage of Female Candidates from Various Cities among total female candidates

Female candidates are 40% of the total candidates.

**The average percentage marks obtained by the candidates from Kolkata was 40% of the maximum marks (maximum marks -200) and the same for Mumbai was 60%. Find the ratio of the average marks obtained by the candidates of these two cities.**- 3 : 2
- 2 : 3
- 3 : 4
- 4 : 3
- 5 : 6
**By what fraction was the number of candidates from Delhi who appeared for the exam less than that from Patna ?**- 5/ 9
- 2/3
- 1/4
- 3/5
- 9/11
**What is the ratio of the total number of candidates appeared from Delhi, Mumbai and Kolkata to the total number of candidates appeared from Patna, Ranchi and Lucknow ?**- 5 : 6
- 3 : 4
- 2 : 3
- 9 : 10
- 10 : 9
**Female candidates from Mumbai are what percent of the total number of candidates from Patna ?**- 43.6
- 42.6
- 41.6
- 40.6
- 45.6
**What is the difference between the total number of candidates from Lucknow and the total number of female candidates from Ranchi ?**- 20380
- 22350
- 21580
- 16359
- 14480

**Directions (Q. No. 11-14) : Study the following pie-chart carefully and answer the questions given below.**

There are five shops P, Q, R, S and T. They sell two different novels - 2 states and Revolution 2020. The following pie-chart shows the total number of novels sold by different shops in the month of July 2017.

Total number of novels sold = 1000

**If the total number of Revolution 2020 sold by shop Q and that by shop R are equal and the ratio of 2 states sold by shop Q to that sold by shop R is 1 : 2, then find the total number of Revolution 2020 Sold by Q and R together ?**- 350
- 265
- 200
- 415
- 375
**If the total number of Revolution 2020 sold by all the shops together is 48% of the total number of novels sold by all the shops, then find the difference between the number of 2 states sold by all the shops together and the number of Revolution 2020 sold by all the shops together ?**- 40
- 35
- 60
- 50
- None of these
**If the total number of novels sold by shop R is 25% more and that sold by Shop T is 15% more in the following month, then what is the total number of novels sold by shop R and T together in the following month ?**- 612
- 720
- 475
- 524
- None of these
**The total number of novels sold by shop P is equal to 48% of the total novels purchased by Shop P. Then what is the total number of unsold novels of shop P ?**- 120
- 210
- 300
- 265
- 130

### Key & Solutions :

**1.**

Marks obtained by all the students in Chemistry = 80 + 110 + 110 + 120 + 60 = 480

Marks obtained by S in Chemistry = 120

=> Required Percentage = (120 / 480) x 100% = 25%

Ans : 1

**2.**

Marks obtained by T in Physics = 50 x (114 / 100) = 57

Now, required percentage

= (57 / 140) x 100% = 40.714 this is approximately equals to 41%

So, Ans : 5

**3.**

Marks obtained by T in Physics = 50

Marks obtained by T in Chemistry = 60

=> Total marks obtained by T in both subjects = 50 + 60 = 110

Marks obtained by R in Physics = 80

Ans : 2

**4.**

Total Marks of P = 130 + 80 = 210

Total marks of T = 50 + 60 = 110

Now, ratio of total marks obtained by P and T

= 210/110 = 21 : 11

Ans : 5

**5**.

Marks obtained by Q in Chemistry = 110

Marks obtained by S in Chemistry = 120

=> Total Marks of Q and S in Chemistry = 110 + 120 = 230

Marks obtained by P in Physics = 130

Marks obtained by R in Physics = 80

=> Total Marks of P and R in Physics = 130 + 80 = 210

Now, required ratio

= 230/210 = 23/21 = 23 : 21

Ans : 2

**6.**

Required ratio = 40 : 60 = 2 : 3

Ans : 2

**7.**

Required fraction = (30000 - 22500) / 30000 = 1/4

**8.**

Total number of candidates from Delhi, Mumbai and Kolkata = (22500 + 27500 + 17500) = 67500

Total number of candidates from Patna, Ranchi and Lucknow = (30000 + 20000 + 25000) = 75000

=> Required ratio

= 67500 : 7500 = 9 : 10

Ans : 4

**9.**

Total number of female candidates

= (25 + 20 + 22.5 + 30 + 17.5 + 2.75) x 1000 x (40/100)

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