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June 06, 2014

SBI PO Data Interpretation Online Practice Tests - Mixed Graphs

22 comments

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Dear SBI PO Online Exam 2014 aspirants, we have already discussed in detail about the concept of Data Interpretation, along with examples of various types. Today we shall discuss about the last type of Data Interpretation, which is Mixed Graphs. In mixed graphs, instead of giving the data in any of the standard formats, they merge two or three formats as one. You have to study them to answer the given questions. Below is a mixed graph which is a combination of bar chart and table. Before going to take the test, read the introductory lessons from below links. Happy Reading :)

The total number of students passed from six different schools is 8000. The given bar-graph shows the proportion of students who passed the exam and the table shows the percentage of students who got 1st, 2nd and 3rd class in the exam. Study the given data and answer the following questions.

 



1st
2nd
3rd
E1
23
45
32
E2
29
48
23
E3
35
30
35
E4
44
24
32
E5
42
36
22
E6
38
37
25
 


1. What is the difference between the total number of students who passed from School E1, E2 and E3 together and that of those who passed from School E4, E5 and E6 together ?
  1. 360
  2. 400
  3. 420
  4. 450
  5. 480
Solution :
(E1 + E2 + E3) = ((8 + 5 + 6) / 40) x 8000

= 3800

(E4 + E5 + E6) = 4200

So, the difference is 400

i.e., Option 2

 2. What is the total number of students who got 1st class in the exam from all the schools together ?
  1. 2350
  2. 2792
  3. 2858
  4. 2916
  5. 2994
Answer : 2858 i.e., Option 3

 3. What is the ratio of the number of students who got 2nd class from School E3 to the number of students who got 3rd class from School E6 ?
  1. 8:3
  2. 9:5
  3. 7:4
  4. 9:7
  5. 5:2
Solution :
 (E3)Second = 1200 x (30 / 100) = 360

(E6)Third = 800 x (25/100) = 200

So, the ratio = 360/200 = 9/5

i.e., Option 2


4. Total number of students who got in 3rd class in School E5, is what percentage of the total number of students passing from all schools together ?
  1.  2.75%
  2. 3.25%
  3. 4.5%
  4. 5.6%
  5. 6.3%
Solution :
(E5)Third = 1000 x (22/100) = 220
So, required % = (220/8000) x 100 = 2.75 %
i.e., Option 1

5. The number of students who got 3rd class in school E1 is what percentage more than the number of students who got 1st class from School E3 ?
  1. 17.8%
  2. 21.9%
  3. 24.6%
  4. 27.2%
  5. 28.6%
Solution :

(E1)Third = 1600 x (32/100) = 512

(E3) First = 1200 x (35/100) = 420

So, Required % = ((512-420) / 420) x 100 = 9200/420

This is approximately equal to 21.9%

i.e., Option 2


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22 comments:

  1. plz upload capsule for sbi po make it fast

    ReplyDelete
  2. Mam how you put 40 at bottom in first solution?
    And
    How you answered 2nd
    In
    3rd one the 1200 and 800?

    ReplyDelete
    Replies
    1. Same question here..pls explain us

      Delete
    2. Hi.
      in 1st ques 40 comes from add all proportions (8+5+6+12+5+4).

      in 2nd ques first find school total student eg
      E1 : (8X 8000)/40=1600.
      now total students passed with !st Class : 1600 X 23%=368.
      similarity find out other school students and then add them and that is anwser.

      in 3rd ques 1200 and 800 comes from proportion bar graph
      E3 : (6X 8000)/40=1200
      E6 : (4 X 8000)/40=800

      Delete
    3. 40 is total of all bars

      Delete
  3. mam pls give us solution of 2nd question

    ReplyDelete
    Replies
    1. assume 8000=40 then 1 part of 8000=200 question asked al 1st class sutdnts means
      in bar graph e1=8parts so 8*200=1600 passed students in that 23% 1st class means 1600*23/100=368
      same process to e2 e3 e4 e5 e6 and finally add all sums=2850

      Delete
  4. This comment has been removed by the author.

    ReplyDelete
  5. Samaj nai aah raha...koi samjao

    ReplyDelete
  6. Mam plz keep on posting these type of data interpretation,

    Thanks lot

    ReplyDelete
  7. mam can u plz tell what question otther than d.i. will be there in apt sec, sbi po plz mam

    ReplyDelete
  8. Plz explain the 2nd question??

    ReplyDelete
  9. Its a very nice set od D.I., please post some more useful sets please

    ReplyDelete
  10. 40 in the bottom is the sum of the proportion of all the schools ie E1+E2+E3+E4+E5 i.e (8+5+6+12+5+4)=40

    ReplyDelete
  11. hai please any one explain 2nd one?

    ReplyDelete
  12. pls explian 2nd one?

    ReplyDelete
  13. Thakyou well sone

    ReplyDelete
  14. 8/40*8000=1600
    E1=1600*23/100=368 similaraly we can calculate others

    ReplyDelete

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