SBI PO Data Interpretation Online Practice Tests - Mixed Graphs

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Dear SBI PO Online Exam 2014 aspirants, we have already discussed in detail about the concept of Data Interpretation, along with examples of various types. Today we shall discuss about the last type of Data Interpretation, which is Mixed Graphs. In mixed graphs, instead of giving the data in any of the standard formats, they merge two or three formats as one. You have to study them to answer the given questions. Below is a mixed graph which is a combination of bar chart and table. Before going to take the test, read the introductory lessons from below links. Happy Reading :)

• Lesson 1 : Introduction
• Lesson 2 : Bar Chart
• Lesson 3 : Pie Chart
• Lesson 4 : Line Chart
• Lesson 5 : Tables 
• Lesson 6 : Paragraphs
• Lesson 7 : Mixed Graphs
• Lesson 8 : Radar Graphs

The total number of students passed from six different schools is 8000. The given bar-graph shows the proportion of students who passed the exam and the table shows the percentage of students who got 1st, 2nd and 3rd class in the exam. Study the given data and answer the following questions.

 

	1st	2nd	3rd
E1	23	45	32
E2	29	48	23
E3	35	30	35
E4	44	24	32
E5	42	36	22
E6	38	37	25

 

1. What is the difference between the total number of students who passed from School E1, E2 and E3 together and that of those who passed from School E4, E5 and E6 together ?

1. 360
2. 400
3. 420
4. 450
5. 480

Solution :

(E1 + E2 + E3) = ((8 + 5 + 6) / 40) x 8000

= 3800

(E4 + E5 + E6) = 4200

So, the difference is 400

i.e., Option 2

 2. What is the total number of students who got 1st class in the exam from all the schools together ?

1. 2350
2. 2792
3. 2858
4. 2916
5. 2994

Answer : 2858 i.e., Option 3

 3. What is the ratio of the number of students who got 2nd class from School E3 to the number of students who got 3rd class from School E6 ?

1. 8:3
2. 9:5
3. 7:4
4. 9:7
5. 5:2

Solution :

 (E3)Second = 1200 x (30 / 100) = 360

(E6)Third = 800 x (25/100) = 200

So, the ratio = 360/200 = 9/5

i.e., Option 2

4. Total number of students who got in 3rd class in School E5, is what percentage of the total number of students passing from all schools together ?

1.  2.75%
2. 3.25%
3. 4.5%
4. 5.6%
5. 6.3%

Solution :

(E5)Third = 1000 x (22/100) = 220

So, required % = (220/8000) x 100 = 2.75 %

i.e., Option 1

5. The number of students who got 3rd class in school E1 is what percentage more than the number of students who got 1st class from School E3 ?

1. 17.8%
2. 21.9%
3. 24.6%
4. 27.2%
5. 28.6%

Solution :

(E1)Third = 1600 x (32/100) = 512

(E3) First = 1200 x (35/100) = 420

So, Required % = ((512-420) / 420) x 100 = 9200/420

This is approximately equal to 21.9%

i.e., Option 2

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