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**1. Rs. 630 is to be distributed amongst Ramu and Kiran in the proportion 7:11. How much would Kiran get ?**

**Solution :**

Total amount = 630

So, total parts = 7+11 = 18

Second part (Kiran's share) = 630 x (11/18) = Rs. 385

So the answer is Rs. 385

if they asks for Ramu's share then

Ramu's share = 630 x (7/18) = Rs. 245

**2. The ratio of two numbers is 3 : 4. The L.C. M of the numbers is 180. What are those numbers?**

**Solution :**

Say required numbers are 3k, 4k

the L.C.M of 3k, 4k is = 12k

So, 12k = 180 => K = 15

So, required numbers 3k = 3 x 15 = 45

4k = 4 x 15 = 60

**3. The ratio of two numbers is 5:7. If you subtract "3" from those numbers, the ratio is 2:3. What are those numbers?**

**Solution :**

Say, the required numbers are 5k, 7k

then (5k-3) / (7k-3) = 2 / 3 [according to the given data]

=> 15k-9 = 14k - 6

=> k = 3

So, required numbers are 15 and 21.

**Shortcut Technique :**

1st ratio = 5 : 7 2nd ratio = 2:3

1st number = (3 x 5) / (15 - 14) = 15

2nd number = (3 x 7) / (15 - 14) = 21

**4. The ratio of two numbers is 4 : 5. The difference between those squares is 81. What are those numbers ?**

**Solution**:

Say the required numbers are 4k, 5k

then (5k)

^{2}-(4k)^{ 2}= 81
9k

^{2}= 81
= > k

^{2}= 9 => k = 3
So, required numbers 4 x 3 = 12 and 5 x 3 = 15

**5. In a committee of 48 members, the ratio of Men and Women are 3 : 1. How many women should join the committee to make the ratio 9 : 5 ?**

**Solution :**

The total members of the committee = 48

The ratio of Men and Women are = 3 + 1 = 4

Total number of men = 48 x (3/4) = 36

Total number of women = 48 x (1/4) = 12

say the required women are k.

So, total women will be 12+k

so, 36 / (12+k) = 9 / 5

then 9 (12 + k) = 36 x 5

= > 108 + 9k = 180 => k = 8

So, the number of required women is 8

**Shortcut Technique :**

The number of Required women = 48 / ((9-5) + 3-1)) = 8

**6. A: B = 2 : 3, B : C = 4 : 5 and C : D = 5 : 7. then A : B : C : D is ?**

**Solution :**

To equate the ratios, the B terms and C terms should be same. But here the value of Bs in the first ratio and second ratio are not equal. In the same way, the values of Cs in the second and third ratios are not equal. SO you should equate them first.

A : B = 2 : 3

you can write this ratio as 8 : 12 (just multiplied both sides with 4)

B : C = 4 : 5

you can write this as 12 : 15 (multiplied both sides with 3)

C : D = 5 : 7

you can write this as 15 : 21 (multiplied both sides with 3)

So,

A : B : C : D = 8 : 12 : 15 : 21

**Shortcut Method :**

A : B : C : D =

(2 x 4 x 5 ) : ( 3 x 4 x 5 ) : (3 x 5 x 5) : (3 x 5 x 7)

= 40 : 60 : 75 : 105

by simplifying them you will get,

8 : 12 : 15 : 21

**7. The ratio of milk and water in a mixture of 50 liters is 3 : 2. How many liters of water should we add to make this ratio 2 : 3 ?**

**Solution :**

Milk in the 50 liters mixture = (3 / (3+2)) x 50 = 30 Liters

Water = 50 - 30 = 20 Liters

assume that you should mix K liters of water to make the ratio 2 : 3

that means (30 / (20 + k)) = 2 / 3

2k + 40 = 90

=> k= 25 Liters

**Shortcut Method :**

Required quantity of water

= ( 50 * (3

^{2}– 2^{2 }) / (2 * (3+2)) = 25 Liters**8. If we subtract a number from 8 : 13, it became 3 : 5. What is that number ?**

**Solution :**

**Say the number is K,**

so, (8-k) / (13-k) = 3/5

=> 3 (13-k) = 5 (8-k)

=> 39 - 3k = 40-5k

=> 5k - 3k = 40-39

=> k = 1/2

**9. The total of two numbers is 49. And the ratio between those two numbers is 2:5. What are those numbers?**

**Solution :**

Assume that those two numbers are 2, 5 (as they are in the ratio of 2:5)

So, the total of those numbers is = 2+5 = 7

But, given that the total is 49

so, the first number is = (2/7)*49 = 14

as you got the first number, the 2nd number is

(14*5) / 2 = 35 [or you can try (5/7)*49]

**10. In an army there are 2100 Soldiers. They have food reserves for 50 days. Some people among them left on leave. Now they can utilize their food reserves for 75 days. How many soldiers left on leave?**

**Solution :**

Assume that the soldiers who left on leave are K

So,

__Soldiers__

__Days__

2100 50

2100 - k 75

if the number of soldiers reduces, the number of days increases. Then,

75 : 50 :: 2100 : (2100 - k)

(75/50) = ((2100/ (2100-k))

4200 = 6300 - 3k

=>3k = 2100 => k = 2100/3 = 700

**Shortcut Method :**

Soldiers left on leave are = (A ( B- C)

**) /**B

here, A = 2100

B = 75 and C = 50

=> (2100 (75-50)) / 75

= (2100 x 25) / 75 = 700

That's all for now friends. If you have any doubts on the methods explained in this post, then feel free to clarify your doubts by using the comments section below. In our next post we shall discuss more model practice problems on Ratio and Proportion which are of higher difficulty level. All the Best and Happy Reading :)

mam puzzle test ka study material daliye aur uska shortcut notes bahut dikkar ho rahi hai puzzl test me ibps po ka

ReplyDeletethanks madam

ReplyDeletethank u mam

ReplyDeleteThanx

ReplyDeletethanks mam it helped me alot. I have a small request if u publish mock tests for current affairs it would be better to all and i hope i can prepare well with this site.Thanks in advance.

ReplyDeleteIts very useful but please provide in PDF, its difficult for me to read on line.

ReplyDeleteThank You

Thanks

ReplyDeleteThanks

ReplyDeletegood one...thanks

ReplyDeleteThanks.

ReplyDeleteThanks a lot.....

ReplyDeleteplz elaborate the shorcut trick used in que no 7...its not clear 3:2 2:3 very confusing

ReplyDeleteIF U UNDERSTAND QUESTION 5 .THEN U CAN SOLVE THIS QUETION BY BOTH WAY LIKE QUESTION 5.

DeleteThanx .. its very useful for me.

ReplyDeleteits nice mam... pls also post some other frequently asked models with short cut...ur shortcuts are very very useful....and easy

ReplyDeleteThnq..But in Short cut methods, pls provide us with some xplntn so that we can undrstnd btr.. thanks in advance...

ReplyDeleteMam shortcut method 1 bhi samj me nahi aayi please explain it

ReplyDeletePlease solve this:

ReplyDeleteIn a fort there was sufficient food for 200 soldiers for 31 days. After 27 days 120 soldiers left the fort. For how many extra days will the rest of the food last for the remaining soldiers?

31-27=4 days left

ReplyDelete200 soldiers----4days

(200-120)=80 soldiers-----(4*200)/80=10 days

food will last for 6 more days

short cut tricks r nt clr :(

ReplyDeletethnx

ReplyDeletethe sides of a triangle are in the ratio 1/2:1/3:1/4 & its perimeter is 100cm then the length of the longest side

ReplyDelete