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Directions (Q. No. 1-5) : The following pie-chart represents the profits earned by a certain company in seven consecutive years. Study the pie-chart carefully and answer the questions.
- If the expenditure in the year 1993 was 30% more than the expenditure in the year 1991, then the income in the year 1993 exceeds the income in the year 1991 by 30% of:
- the income in the year 1991
- the expenditure in the year 1993
- the income in the year 1993
- the expenditure in the year 1991
- None of these
- If x% of the total of profits earned in all the given years is same as the profit earned in the year 1994, then x is:
- 16 2/3
- 33 1/3
- 12 1/2
- 11 2/3
- 10 3/5
- The ratios of expenditures and incomes in the years 1992, 1994 and 1996 are given to be 6:5:8 and 2:3:4 respectively. The ratio of the income in the year 1996 to the total expenditure in the years 1992 and 1994 is :
- 40 : 11
- 10 : 7
- 20 : 11
- 20 : 13
- 11: 12
- The year in which the profit is nearest to the average of the profits earned in all the given years is :
- 1991
- 1995
- 1993
- 1994
- 1992
- If the income in the year 1997 was 5 times the expenditure made in the same year, then the ratio of the profit earned in the year 1991 to the expenditure in the year 1997 was :
- 11 : 28
- 44 : 7
- 28 : 11
- 7 : 44
- 14 : 45
Solutions :
1.
The expenditure in the year 1991. It is clear from the question. So, the Answer is : Option 4.
2.
x% of 100 = 16.67%
=> x = 16 2/3 %
So answer is : Option 1
3.
Option :3
4.
Average = (42 + 66 + 72 + 54 + 60 + 42 + 24) / 7 = 51.4. This is approximately equal to the profit of the year 1995.
So the answer is : Option 2
5.
1997 => Income = 5 x Exp.
=> Profit = 4Exp
=> 4Exp = 66 => Exp = 66/4
=> Required Ratio = 42 : 66/4
= 42 x 4 : 66 = 28 : 11
So the answer is : Option 3
Shared by Shravan Varma Gadiraju
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