Explanations for SBI Associate Clerks Online Aptitude Test 3

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Friends, these are the answers with explanations to our Online Test of SBI Assocaite Clerks. Please take the Online Test from here before checking these solutions... 

1. (25)³  / 625  x 5⁵ = (5)^?

=> (5⁶ x 5⁵) / 5⁴ = ?

=>  5^6+5-4 = 5^?

=> ? = 7

2.  23 x 15 / 25 - ? +48.2 = -35

=> ?  = ((23x15)/25) + 48.2+35 = 97

3.  120 x ? = 10 / ((126x0.5)/(63x2))x12

=> 120 x ? = 10 / (1/2) x 12

=> ? = 240/120 = 2

4. ((12)^-2   ) ²  / ((12) ²  )^-2   = ?

=> ? =  (1/144) ²  / (144)^-2   =  (144) ²  / (144)²   = 1

5.  9^10.5   x 9^5.1   / 9^5.1   = 9<sup>? 

=></sup>  9^10.5+5.1-1.2= 9<sup>?

=>  ? = 10.5+5.1-1.2 = 14.4</sup>

6. 
(Maths + English) / 2 = 75

=> Maths + English = 150 --------------------- Say Equation (1)

(Maths + Science) / 2 = 65

=> Maths + Science = 130 ------------------------ Say Equation (2)

Subtracting (1) from (2), English - Science = 20


7. Let the cost price of A be Rs. 100, then the selling price = Rs. 115

Now, the cost price of B be Rs. 115

Selling Price of B = (110/100) x 115 = 126.50


But the cost price of C given as Rs. 506

If the cost price of C is Rs. 126.50, then the C.P of A = Rs. 100


If the cost price of C is Rs. 506, then the C.P  = (506/126.50) x 100 = Rs. 400

Shortcut Technique :

Let the C.P of A be Rs. X, then

115% of 110% of X = Rs. 506

(115/100) x (110/100) x X = 506

=> X = 506 x (100/115) x (100/110) = Rs. 400

8.

Let the first and second numbers be X and Y

So, X x (40/100)+y = 1.2 Y

=> (2/5) x X = 1.2Y-Y  =>  2X = 0.2Y x 5 = Y

=> X/Y = 1/2  => X:Y = 1:2


9.

Let the number of Rs. 1, 50 paise and 25 paise coins be 2, 3 and 10 respectively.

The value of one rupee coins = Rs. 1 x 2 = Rs. 2

The value of fifty paise coins = Rs. 0.50 x 3 = Rs. 1.50

The value of twenty five paise coins = Rs. 0.25 x 10 = Rs. 2.50

Total value = 2 + 1.5 + 2.5 = Rs. 6

If the total value is Rs. 6, there are 10 coins of 25 paise

If the total value is Rs. 288, then the number of 25 coins = (288/6) x 10 = 480


10. 
When two variables are inversely proportional, one is 'X' percent more / less than the second one,

then the second one is ( X / (100+X)) or (X / (100-X)) percent less / more than the first one.

(if first one is more, then use '+' and if it is less then use '-')

So, Reduction in the consumption = (20/120) x 100  = 16(2/3)%

11. 

Let the speed of the boat be 'X' kmph

Time to cover 90 km downstream  = 90 km / (X+2) kmph

Time to cover 66 km upstream = 66 km / (X-2) kmph

But the time to cover both the distances is same

So, (90/(X+2)) = (66/(X-2)) = >  X = 13 kmph

12.

Distance = 300 km.  Time =4/5 of 5 = 4 hours

Required speed = Distance / Time = 300/4  = 75 kmph

13.

Work done by 16 men in 16 days = 1

So, work done by 16 men in 4 days = 4/16 = 1/4

Remaining work = 1-(1/4) = 3/4

Total number of men now = 16+8 = 24

16 men do 1 work in 16 days

24 men do 3/4 work in (16 x 16 x 3) / (24 x 4) = 8 days

Shortcut Technique :

Total mandays required for the work = 16 x 16 = 256

Number of mandays completed in 4 days = 4 x 16 = 64

Remaining mandays = 256 - 64 = 192

Number of men available now = 16 + 8 = 24

So, Number of days required = 192 / 24 = 8

14. 

LCM of 4, 5 and 6 is 60

So, the ratio = 60/4 : 60/5 : 60/6  = 15: 12:10

C's share = (10/(15+12+10)) x 11840 = (10/37) x 11840 = 3200

15.

7! = 5040

16.

Average Male population = (45+42+25+35+32+35+36) / 7 

= 250/7 = 35.71 hundred

17.

Required percent = (25/20) x 100 = 125%

19.

Male population = 45 + 42 + 25 + 35 + 32 + 35 + 36

= 250

Female population = 36 + 50 + 20 + 40 + 25 + 45 + 40

= 256

So, the difference = 256 - 250 = 6 hundred

Shortcut Technique :

(45-36) + (42-50) + (25-20) + (35-40) + (32-25) +(35-45)+(36-40)

=> 9 - 8 + 5 - 5 + 7 - 10 - 4 = -6

So, the difference is 600

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