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This Vedic Math Shortcut method is applicable when,
- The sum of the digits in units place is 10.
- The digits in the higher places (on LHS) of both the numbers are same.
Now lets try to understand the above rules with a small example.
Example 1 : 43 x 47 = ?
- Here, the digits in the units place of both the given numbers are 3 and 7 respectively. Adding them, we get 3
+ 7 = 10. So first condition satisfied. - The digits in the 10's place (on LHS) of both the numbers are 4 only. So the second condition is also satisfied.
So, our shortcut method is applicable for this problem. Now lets have a look at the solution of 43 x 47 = ?
- Initially : 3 x 7 = 21
- Ekadhika : 4 + 1 = 5
- Next : 4 x 5 = 20
- Result : 43 x 47 = 20 | 21 = 2021 ----> This is the answer
Confused ? Let's have a look at another example,
Example 2 : 74 x 76 = ?
- The digits in the units place of both the given numbers are 4 and 6 respectively. Adding them, we get 4+6 = 10
- The digits in the 10's place (on LHS) of both the numbers are 7 only.
- Initially : 4 x 6 = 24
- Ekadhika : 7
1 = 8+ - Next : 7 x 8 = 56
- Result : 74 x 76 = 56 | 24 = 5624 ----> This is the answer
Let's see another Example,
Example 3 : 62 x 68 = ?
- The digits in the units place of both the given numbers are 2 and 8 respectively. Adding them, we get 2+8 = 10
- The digits in the 10's place (on LHS) of both the numbers are 6 only.
- Initially : 2 x 8 = 16
- Ekadhika : 6
+ 1 = 7 Next : 7 x 6 = 42 Result : 62 x 68 = 42 | 16 = 4216 ----> This is the answer
That's all for now friends. In our next post we shall discuss more vedic maths shortcut techniques. Happy Reading :)
Read more Vedic Maths Shortcuts from here

About The Author
Rupali Shete (M.Sc., M.Phil., Ph.D) is a gold medalist from Osmania University (Hyderabad), one of the working members of Rananujan Mathematics Academy and Institute of Scientific Research on Vedas (ISERVE), Currently working in University of Pune.
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