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Set 1 :
1.
Let the number of days he present be "X" days
So, 50X -10 (30 - X) = Rs. 1200 => X = 25
2.
Let the distance between A and B be "X" km
So, ((X / (9-3)) + ((x / (9+3)) = 3 hours
=> X = 12 km
3.
9C3 - 6C3
4.
For the least number of tiles, the tile should be of largest size.
Longest size of tile = HCF of length and breadth of the floor.
HCF of 725 cm and 575 cm = 25 cm
So, Least number of tiles = ((725 x 575) / (25 x 25)) = 667
5.
Sum of the ages of husband and wife 6 years ago = 2 x 22 = 44 years
Their total age at present = 44 + 6 + 6 = 56 years
Sum of the ages of husband, wife and child at present = 56 + 4 = 60
Average age of whole family at present = 60 / 3 = 20 years
Set 2
1.
Number of articles sold by P = 27.5 % fo 35 lakh = 962500
Number of articles sold by Q = 20% of 30 lakh = 600000
Total articles = 962500 + 600000 = 1562500
2.
Average articles manufactured = (25 + 22.5 + 30 + 35 + 32.5 + 30) / 6 = 175 / 6
= 29.167 lakhs
3.
80% of 2500000 : 85% of 3000000 = 40 : 51
4.
Number of articles sold in 2007 = 35% of 3250000 = 1137500
Number of articles sold in 2005 = 15% of 3000000 = 450000
Increment % = (687500 / 450000) x 100 = 152.78
Set 3 :
1.
(108 - 98) / 98) x 100 this is approximately equals to 10%
2. 2005
3.
2002 (48 / 56) x 100 = 85.71%
2003 (56 / 78) x 100 = 71.79%
2004 (72 / 94) x 100 = 76.59%
2005 (70 / 85) x 100 = 82.35%
2006 (90 / 92) x 100 = 97.82%
4.
A (86 / 110) x 100 = 78.18%
B (70 / 85) x 100 = 82.35%
C (90 / 102) x 100 = 88.23%
D (102 / 112) x 100 = 91.07%
E (98/108) x 100 = 90.74%
5. 2006
Set 4
1.
21 + 512 = 533
533 + 343 = 876
876 + 216 = 1092
1092 + 125 = 1217
1217 + 64 = 1281
2.
17 x 1 + 3 = 20
20 x 2 + 5 = 45
45 x 3 + 7 = 142
142 x 4 + 9 = 577
577 x 5 + 11 = 2896
3.
5 x 8 - 24 = 16
16 x 7 - 24 = 88
88 x 6 - 24 = 504
504 x 5 - 24 = 2496
2496 x 4 - 24 = 9960
4.
2.5 + 12 = 3.7
3.7 + 2.4 = 6.1
6.1 + 4.8 = 10.9
10.9 + 9.6 = 20.5
20.5 + 19.2 = 39.7
5. All are one less than perfect squares except 362.
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waiting eagerly Sir ji :)
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