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**Data Interpretation (CI) Practice Test for IBPS PO VII Main Exam 2017 **

**Directions (Q. No. 1 - 5): Study the following bar graph carefully to answer the questions.**

Marks obtained by five students in Physics and Chemistry

**Marks obtained by S in Chemistry is what percent of the total marks obtained by all the students in Chemistry ?**- 25%
- 28.5%
- 35%
- 31.5%
- 22%
**If the marks obtained by T in Physics were increased by 14% of the original marks, then what would be his new approximate percentage in Physics, when the maximum marks in Physics were 140 ?****Total marks obtained by T in both the subjects together is more than the marks obtained by :**- Q in Chemistry
- R in Physics
- S in Chemistry
- P in Physics
- R in both the subjects together
**What is the respective ratio between the total marks obtained by P in Physics and Chemistry together to the total marks obtained by T in Physics and Chemistry together ?**- 3 : 2
- 4 : 3
- 5 : 3
- 2 : 1
- None of the above
- What is the respective ratio between the total marks by Q and S together in Chemistry to the total marks obtained by P and R together in Physics ?
- 23 : 25
- 23 : 21
- 17 : 19
- 17 : 23
- None of the above

**Directions (Q. No. 6 -10) : Study the following bar-chart and piechart to answer the questions given below.**

Number of candidates (in thousand) who appeared for the IBPS Exams from six different cities.

Percentage of Female Candidates from Various Cities among total female candidates

Female candidates are 40% of the total candidates.

**The average percentage marks obtained by the candidates from Kolkata was 40% of the maximum marks (maximum marks -200) and the same for Mumbai was 60%. Find the ratio of the average marks obtained by the candidates of these two cities.**- 3 : 2
- 2 : 3
- 3 : 4
- 4 : 3
- 5 : 6
**By what fraction was the number of candidates from Delhi who appeared for the exam less than that from Patna ?**- 5/ 9
- 2/3
- 1/4
- 3/5
- 9/11
**What is the ratio of the total number of candidates appeared from Delhi, Mumbai and Kolkata to the total number of candidates appeared from Patna, Ranchi and Lucknow ?**- 5 : 6
- 3 : 4
- 2 : 3
- 9 : 10
- 10 : 9
**Female candidates from Mumbai are what percent of the total number of candidates from Patna ?**- 43.6
- 42.6
- 41.6
- 40.6
- 45.6
**What is the difference between the total number of candidates from Lucknow and the total number of female candidates from Ranchi ?**- 20380
- 22350
- 21580
- 16359
- 14480

**Directions (Q. No. 11-14) : Study the following pie-chart carefully and answer the questions given below.**

There are five shops P, Q, R, S and T. They sell two different novels - 2 states and Revolution 2020. The following pie-chart shows the total number of novels sold by different shops in the month of July 2017.

Total number of novels sold = 1000

**If the total number of Revolution 2020 sold by shop Q and that by shop R are equal and the ratio of 2 states sold by shop Q to that sold by shop R is 1 : 2, then find the total number of Revolution 2020 Sold by Q and R together ?**- 350
- 265
- 200
- 415
- 375
**If the total number of Revolution 2020 sold by all the shops together is 48% of the total number of novels sold by all the shops, then find the difference between the number of 2 states sold by all the shops together and the number of Revolution 2020 sold by all the shops together ?**- 40
- 35
- 60
- 50
- None of these
**If the total number of novels sold by shop R is 25% more and that sold by Shop T is 15% more in the following month, then what is the total number of novels sold by shop R and T together in the following month ?**- 612
- 720
- 475
- 524
- None of these
**The total number of novels sold by shop P is equal to 48% of the total novels purchased by Shop P. Then what is the total number of unsold novels of shop P ?**- 120
- 210
- 300
- 265
- 130

### Key & Solutions :

**1.**

Marks obtained by all the students in Chemistry = 80 + 110 + 110 + 120 + 60 = 480

Marks obtained by S in Chemistry = 120

=> Required Percentage = (120 / 480) x 100% = 25%

Ans : 1

**2.**

Marks obtained by T in Physics = 50 x (114 / 100) = 57

Now, required percentage

= (57 / 140) x 100% = 40.714 this is approximately equals to 41%

So, Ans : 5

**3.**

Marks obtained by T in Physics = 50

Marks obtained by T in Chemistry = 60

=> Total marks obtained by T in both subjects = 50 + 60 = 110

Marks obtained by R in Physics = 80

Ans : 2

**4.**

Total Marks of P = 130 + 80 = 210

Total marks of T = 50 + 60 = 110

Now, ratio of total marks obtained by P and T

= 210/110 = 21 : 11

Ans : 5

**5**.

Marks obtained by Q in Chemistry = 110

Marks obtained by S in Chemistry = 120

=> Total Marks of Q and S in Chemistry = 110 + 120 = 230

Marks obtained by P in Physics = 130

Marks obtained by R in Physics = 80

=> Total Marks of P and R in Physics = 130 + 80 = 210

Now, required ratio

= 230/210 = 23/21 = 23 : 21

Ans : 2

**6.**

Required ratio = 40 : 60 = 2 : 3

Ans : 2

**7.**

Required fraction = (30000 - 22500) / 30000 = 1/4

**8.**

Total number of candidates from Delhi, Mumbai and Kolkata = (22500 + 27500 + 17500) = 67500

Total number of candidates from Patna, Ranchi and Lucknow = (30000 + 20000 + 25000) = 75000

=> Required ratio

= 67500 : 7500 = 9 : 10

Ans : 4

**9.**

Total number of female candidates

= (25 + 20 + 22.5 + 30 + 17.5 + 2.75) x 1000 x (40/100)

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